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• Solve This Sum: Math Problem Solver

  Use our Math Problem Solver to get your maths questions answered for free! No SIgnup Required!

• Solve This Sum: For equation ax^2 + bx + c = 0, find the condition such that one root may be (i) 4

  One root is m times the other. We can assume them as t and mt. Sum of roots = -b/a t + mt = -b/a (m+1)t = -b/a t = -b/a(m+1) Product of roots = c/a t * mt = c/a mt^2 = c/a ...

• Solve This Sum: Equation x^2 + 3x + 1 = 0 has roots a, b. Find the equation whose roots are (i) a/b

  Equation x^2 + 3x + 1 = 0 has roots a, b. By using Sum and Product of roots formulae a + b = -3 a.b = 1 Also, any Quadratic equation can be written as x^2 - (sum of its roots)x + (product of its roots...

• Solve This Sum: 2013

  A website with maths problems and solutions. Use our math problem solver to ask a question.

• Solve This Sum: Roots of equation (x^2 - bx) / (ax - c) = (p - 1) / (p + 1) are equal in magnitude

  Roots are equal in magnitude but opposite in sign. Therefore, sum of them will be equal to 0.The equation is (x^2 - bx) / (ax - c) = (p - 1) / (p + 1) = (p + 1)x^2 + (a - b - ap - bp)x + pc - c = 0 S...

• Solve This Sum: If equation ax^2 + bx + c = 0 has roots Alpha and Beta, find values of these

  equation ax^2 + bx + c = 0 has roots alpha and beta 1) α^4 + β^4 2) α^2/β + β^2/α 3) α^3/β + β^3/α 4) 1/(aα + b) + 1/(aβ + b) => (α²)² + (β²)² => (α² + β²)² - 2α²β² by using a² + b² = (a + b)...